As I continue to do more and more research about Carnauba, I'm becoming more and more convinced that ZV is, in fact, a superior product.
From what I've learned so far, (and some of what I knew previously), carnauba is extremely hard, is NOT readily soluble, has an extremely high melting point, and can not be broken down by water.
That sounds like something I want on my car paint, doesn't it??
However, those properties make it nearly impossible to get pure carnauba from the Brazillian Carnauba Palm Tree, onto your car. Oils and solvents, and mixing carnauba with other, more forgiving waxes makes it easier.
Therefore, as the content of pure carnauba goes up, the oils, solvents, and other waxes need to work harder in order to make the product more spreadable. Or, they need to be higher quality oils, solvents, and waxes. However, when these products evaporate from the surface of the car all that's left is carnauba.
This also explains the "hand" application of ZV. Heat is known to aid in the breakdown of carnauba wax. Therefore, since ZV contains such a high volume of such a resilient product, the introduction of heat aids in the application process. How is this accomplished? From what I've read, ZV contains certain enzymes that interact with your own body head and act as a catalyst to aid in the application of the wax.
Furthermore, the 61% by volume shouldn't be so difficult to understand. Since carnauba is what's left behind after the evaporation of the solvents, it stands to reason that a higher carnauba content would leave a thicker, more durable protective coat. For example: if Brand X contains 5% carnauba and ZV contains 61%. Then it stands to reason that applying 1oz of Brand X will leave your car with .05 oz of carnauba protection. Whereas 1oz of ZV will leave .61oz of carnauba protection. Since your car is a finite size, that means that the protective coating must be thicker and harder when using ZV.
And, since the ZV coating is thicker, it stands to reason that it is more durable. Just like a large chunk of ice takes longer to melt than a small chunk, .61oz of carnauba will take longer to break down than .05oz given the same driving conditions.
This is all basic info I know. I got it from wikipedia and wisegeek.com. I'm still learning, but it seems that this information supports the idea that a 61% carnauba formula should cost more. 1) It takes higher quality, more specialized ingredients to make it work. And 2) It seems logical that it would perform better than Brand X because it leaves behind MORE protective wax.
Please don't come back at me with "Why does more = better" I just attempted to explain it, and I think I did a pretty good job.
From what I've learned so far, (and some of what I knew previously), carnauba is extremely hard, is NOT readily soluble, has an extremely high melting point, and can not be broken down by water.
That sounds like something I want on my car paint, doesn't it??
However, those properties make it nearly impossible to get pure carnauba from the Brazillian Carnauba Palm Tree, onto your car. Oils and solvents, and mixing carnauba with other, more forgiving waxes makes it easier.
Therefore, as the content of pure carnauba goes up, the oils, solvents, and other waxes need to work harder in order to make the product more spreadable. Or, they need to be higher quality oils, solvents, and waxes. However, when these products evaporate from the surface of the car all that's left is carnauba.
This also explains the "hand" application of ZV. Heat is known to aid in the breakdown of carnauba wax. Therefore, since ZV contains such a high volume of such a resilient product, the introduction of heat aids in the application process. How is this accomplished? From what I've read, ZV contains certain enzymes that interact with your own body head and act as a catalyst to aid in the application of the wax.
Furthermore, the 61% by volume shouldn't be so difficult to understand. Since carnauba is what's left behind after the evaporation of the solvents, it stands to reason that a higher carnauba content would leave a thicker, more durable protective coat. For example: if Brand X contains 5% carnauba and ZV contains 61%. Then it stands to reason that applying 1oz of Brand X will leave your car with .05 oz of carnauba protection. Whereas 1oz of ZV will leave .61oz of carnauba protection. Since your car is a finite size, that means that the protective coating must be thicker and harder when using ZV.
And, since the ZV coating is thicker, it stands to reason that it is more durable. Just like a large chunk of ice takes longer to melt than a small chunk, .61oz of carnauba will take longer to break down than .05oz given the same driving conditions.
This is all basic info I know. I got it from wikipedia and wisegeek.com. I'm still learning, but it seems that this information supports the idea that a 61% carnauba formula should cost more. 1) It takes higher quality, more specialized ingredients to make it work. And 2) It seems logical that it would perform better than Brand X because it leaves behind MORE protective wax.
Please don't come back at me with "Why does more = better" I just attempted to explain it, and I think I did a pretty good job.