Help with Calculus?

B

BMW335i

New member
Can anyone solve this for me in y=mx+b form?



- Find the equations of the tangent lines at the points (1,5) and (2,3).



How you got the answer would be greatly appreciated.





P.S. I feel pretty silly asking a detailing forum about this but I know alot of you guys are smart so its worth a shot :2thumbs:



function is y = 3 + 4x^2 - 2x^3
 
I feel for you, honestly. I'm one of those that could not comprehend Jr. High algebra......with a brilliant tutor. Sorry I can't be of help.
 
Just in case you're still unclear or anyone else needs to know...here are the steps:



1. Differentiate the function. The derivative will be the slope ("m") of the y=mx+b form, because derivatives are, by definition, the slope of the tangent line.



2. Assuming you're doing this in point-slope form, take the coordinates (in this case first (1,5)) and plug it into the form so that the result is (y-5)=m(x-1), which then you should be able to simplify to get a resulting y=mx+b equation.
 
y=mx+b is the equation for finding the slope of a line (as mentioned).



That's Algebra not Calculus.



MorBiD
 
Yep, it's algebra... linear equation by plotting the y-intercept, and plotting another point by using the slope of the line. It could be a course that leads you into Calculus with a little warm-up from Algebra.



Wait a minute... this is a detailing forum. I'm here to de-stress. If anything, we should be discussing chemistry. Like what is the cross-linking molecular structure of polymers vs. simple carnuba wax?
 
You know, there are threads here that discuss that very topic. But at university my majors required lots of math and no chemistry so I stay out of it :)
 
If you still can't get it let me know... I will be checking this post for an hour, if you need it I will give you my cell phone number and I will talk you through the equation/calculations.



Math is one of those things that when you see the path you never forget it. If you don't see the path, then no map in the world can help.
 
tyymm said:
If you still can't get it let me know... I will be checking this post for an hour, if you need it I will give you my cell phone number and I will talk you through the equation/calculations.



Math is one of those things that when you see the path you never forget it. If you don't see the path, then no map in the world can help.
Click to expand...



Thanks for the generous offer, but I got the answer (turned out to be pretty simple). I really appreciate you wanting to help!



BTW - to the previous posters, this is Calculus, you need limits to solve the problem.
 
limits? Hum, have you all learned differentiation yet? It'll get a lot easier after that. You won't have to worry about that long formula with limits and all.
 
^ LOL



Paul, I need you in my calculus test today!



limits? Hum, have you all learned differentiation yet? It'll get a lot easier after that. You won't have to worry about that long formula with limits and all.
Click to expand...

:hairpull school systems like to make things really hard and complicated. :P he should know how to do it in 10secs by next week.
 
lets see if I carry the 2 add 5 and minus the tangent, divide the sum of the mulitale by 33 and square that... I thinnk it would be something like -5.3224...



I have no idea...and thats why im in the military :usa
 
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